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问题如图,△ABC的面积为△,AF/AC=1/b,CE/CB=1/a,BD/BA=1/c(a、b、c为正实数)求△GHM的面
The problem is shown in the figure. The area of △ABC is △, AF/AC=1/b, CE/CB=1/a, and BD/BA=1/c (a, b, and c are positive real numbers).