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2013年湖南高考数学理科卷第8题:在等腰直角三角形ABC中,AB=AC=4,点P是边AB上异于A,B的一点,光线从点P出发,经BC,CA反射后又回到点P(如图1),.若光线QR经过ΔABC的重心,则AP等于A.2 B.1C.8/3D.4/3笔者利用它的特殊图形可以很快找到正确答案,然而一想,若该题光线经过的不是重心,恐怕很多答题人都会遇到
In 2013 Hunan College Mathematics Mathematics Book 8: In the isosceles right angle triangle ABC, AB=AC=4, point P is a point on the side AB that is different from A and B. The light starts at point P and reflects by BC and CA. Then back to point P (as shown in Figure 1), if the light QR passes the center of gravity of ΔABC, then the AP is equal to A.2 B.1C.8/3D.4/3 I can quickly find the correct answer using its special graphics. However, if one thinks that if the light is not center of gravity, I’m afraid that many people will encounter