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本文把水声信道模型看成是莱斯(Rice)和瑞利(Rayleigh)信道,求得了FSK码的符号误差概率P_E、FSK组码的位误差概率P_b~1和FSK卷积码的位误差概率P_b。计算结果表明,信号确定性分量的贡献出现在P_E表式的指数部份,信号的随机分量出现在表式的线性反比部份。当信号确定性分量上升时,P_E迅速下降;在相同P_b和P_b~1的情况下,一种简单的卷积码所需频带宽度比组码小得多。在水声通讯应用方面,卷积码非常重要。
In this paper, the acoustic channel model is regarded as Rice and Rayleigh channels, the symbol error probability of FSK code P_E, the bit error probability P_b ~ 1 of FSK code and the bit error of FSK convolutional code Probability P_b. The results show that the contribution of the deterministic component of the signal appears in the exponential part of the P_E table, and the random component of the signal appears in the linear inversely proportional part of the table. P_E declines rapidly as the deterministic component of the signal increases; in the case of the same P_b and P_b ~ 1, the bandwidth required for a simple convolutional code is much smaller than the group code. Convolutional codes are very important for underwater acoustics applications.