《中小学数学》(初中版)2009年第9期刊,《再循伽莫夫奇思妙想之迹》一文,笔者研读后,深有启发,特别是对文中未证之猜想颇感兴趣,尝试证明,与大家共享.先摘录原文奇思妙想总结:按正整数顺序排列的一列数:若后一项与前一项的差值为一列常数,则这列数与顺序数的对应关系满足一次函数;若后一项与前一项的差值不为一列常数, “Primary and secondary mathematics” (junior high school edition) in 2009 ninth issue, “revisit Gamow Wonderful traces of” article, the author after reading, inspired by, especially the article is not evidence of conjecture quite interested, Try to prove that, to share with you. The first excerpt The original whimsy to sum up: According to a sequence of positive integer number of columns: If the difference between the latter and a column of a constant, then the number of columns and the correspondence between the sequence number Satisfy a function; if the difference between the last item and the previous item is not a constant,