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Ⅰ.問题的提出問題:甲乙丙三人共有384元、先由甲分給乙內,所給之數如乙丙所有之數,繼由乙分給甲丙,末由內分給甲乙,給法同前。結果,三人所有之錢數恰巧相等,問各人原有錢多少? 首先用算術及代數兩種方法來解答。 (一) 算術法: 先列出最後的結果(即丙給甲乙後)為每人384元+3=128元,再倒退計算至各人原有為止。結果,甲原有208元,乙原有112元,丙原有64元,列得算式如下:甲原有:384÷3÷2÷2+(384-384÷3÷2÷2)÷2=208(元);乙原有:[384÷3÷2+(384-384÷3÷2)÷2]÷2=112(元);丙原有:384-208-112=64(元)。
I. Question raised: A, B, C, B, C, C, B, C, B, C, B, C, B, B, C, B, C, B, C, B Law with the former. As a result, the amount of money for all three people happens to be equal, and ask how much money each person has originally. First, use arithmetic and algebraic methods to answer. (1) Arithmetic method: First list the final result (that is, after C to A and B) for 384 yuan + 3 = 128 yuan per person, and then count back to the original. As a result, A is 208 yuan, B is 112 yuan, and C is 64 yuan. The formula is as follows: A: 384÷3÷2÷2+(384-384÷3÷2÷2)÷2= 208 (yuan); B original: [384÷3÷2+(384-384÷3÷2)÷2]÷2=112(yuan); C原有 original: 384-208-112=64 (yuan).