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本文所选的二道计算题,学生题解的错误率很高。从中可看出学生的知识缺陷,值得引起教师的注意。〔例一〕19.05克的铜与稀HNO_3全部反应,计算有多少摩尔的硝酸被还原。〔误答〕 3Cu+8HNO_3=3Cu(NO_3)_2+2NO~+4H_2O 63.5×3克 8摩 19.05克 x x=((8×19.05))/190.5=0.8(摩)
The two-choice questions selected in this article have a high error rate for students’ solutions. From this we can see that the students’ knowledge defects are worthy of their attention. [Example 1] All 19.05 grams of copper reacted with dilute HNO 3 to calculate how many moles of nitric acid were reduced. [Answer] 3Cu+8HNO_3=3Cu(NO_3)_2+2NO~+4H_2O 63.5×3g 8Motor 19.05g x x=((8×19.05))/190.5=0.8(Motor)