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一、热力学定律与气体状态变化的分析判断例1(山东理综)如图1所示,喷雾器内有10 L水,上部封闭有1 atm的空气2 L.关闭喷雾阀门,用打气筒向喷雾器内再充入1atm的空气3 L(设外界环图1境温度一定,空气可看做理想气体).(1)当水面上方气体温度和外界温度相等时,求气体压强,并从微观上解释气体压强变化的原因.(2)打开喷雾阀门,喷雾过程中封闭气体可以看成等
First, the laws of thermodynamics and analysis of changes in gas conditions and judgments Example 1 (Shandong Lihong) As shown in Figure 1, the sprayer has 10 L of water, the upper closed 1 atm of air 2 L. Close the spray valve, with the pump to the sprayer The air is recharged with 1atm of air 3L (set the ambient temperature of the outer ring to a certain temperature, the air can be regarded as the ideal gas). (1) When the gas temperature above the water surface is equal to the outside temperature, the gas pressure is calculated and interpreted from the microscopic point of view Causes of gas pressure changes. (2) Open the spray valve. The closed gas can be considered as