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人体肿瘤,如支气管粘膜肿瘤的自体荧光与正常组织的自体荧光存在差异,据此进行肿瘤的检测是可能的。但是,人们还不清楚这种差异性是否足够大,以及什么是最佳的激发波长和发射波长。作者测量了人肺肿瘤试样的自体荧光激发光谱,分别在520nm和690nm2种发射波长处测得激发谱与300nm到600nm激发波长的函数关系。用405nm和一些更长的波长激发,也测量了人肺组织和肿瘤试样在500nm到750nm波长范围的自体荧光发射谱。在略小于约600nm的一段光谱区,肿瘤发射的荧光小于正常组织的荧光。结果表明,单独用二者自体荧光的差异有可能提供一种探测肿瘤的新方法。
Human tumors, such as autofluorescence of bronchial mucosal tumors and autofluorescence of normal tissues, are different. Therefore, it is possible to detect tumors. However, it is unclear whether this difference is large enough and what is the optimal excitation wavelength and emission wavelength. The authors measured the autofluorescence excitation spectra of human lung tumor samples, and measured the excitation spectra as a function of excitation wavelength from 300 nm to 600 nm at two emission wavelengths of 520 nm and 690 nm, respectively. Excited at 405 nm and some longer wavelengths, autofluorescence emission spectra of human lung tissue and tumor samples in the wavelength range of 500 nm to 750 nm were also measured. In a spectral region slightly less than about 600 nm, the tumor emits less fluorescence than normal tissues. The results show that the difference in autofluorescence between the two may provide a new method for detecting tumors.