在有机物的推断或推理计算中,常遇到这样一个问题:知道(或求出)有机物的分子量后,要确定所求的物质是某种(或可能是哪些) 反过来说,将已知(或求出)有机物的分子量(M)除以14以后,得商的整数部分和余数。若余数为4,则所求的有机物可能为一分子中含碳原子数比商的整数部分少1的饱和一元醇或 In the inferring or inferential calculation of organic matter, one often encounters such a problem: after knowing (or finding) the molecular weight of organic matter, it is necessary to determine what kind of material (or what may be) the material sought is, in turn, known to be ( Or find) the molecular weight (M) of organics divided by 14, the quotient of the integer part and the remainder. If the remainder is 4, the organics sought may be saturated monohydric alcohols with 1 or less carbon number in the molecule than the integer part of the quotient.