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1979年高等学校招生考试化学试题第六题: 1.把氯气通入浓氨水中发生下列反应: 3Cl_2+8NH_3=6NH_4Cl+N_2使1.12升氯、氮混和气体(90%Cl_2和10%N_2)通过浓氨水。实验测得逸出的气体(除NH_3后)体积为0.672升(50%Cl_2和50%N_2)。问反应中有多少克氨被氧化?(体积已换算成标准状况) 解一: 3CL_2+2NH_3+6NH_3=6NH_4Cl+N_2 (1)根据方程式由NH_3生成N_2的体积为:
In the 1979 Higher Education Admissions Exam Chemistry Questions 6: 1. The following reactions occurred when chlorine was introduced into concentrated ammonia water: 3Cl_2+8NH_3=6NH_4Cl+N_2 passed 1.12 liters of chlorine and nitrogen mixture gas (90% Cl_2 and 10% N_2) Concentrated ammonia. The volume of gas evolved after the experiment (excluding NH 3 ) was 0.672 liters (50% Cl 2 and 50% N 2 ). Ask how many grams of ammonia are oxidized in the reaction? (Volume converted to standard conditions) Solution one: 3CL_2+2NH_3+6NH_3=6NH_4Cl+N_2 (1) The volume of N_2 produced by NH_3 according to the equation is: