“若若”型探索题的形式是“若能…:若不能…”或“若存在…:若不存在…”.解决这类问题的思路是假设结论肯定,然后导出某个结论.如果该结论合理,则说明假设成立,所探索结论为肯定;如果该结论不合理,则说明假设错误,所探索结论为否定.例1已知一次函数y=kx+b(k≠0)和反比例函数y=k/2x的图象交于点A(1,1). “If ... ” or “if exists ...: if it does not exist ... ”. The idea of ​​solving this type of problem is to assume the conclusion is affirmative and then export If the conclusion is reasonable, then the hypothesis is established, the conclusion of the exploration is affirmative; if the conclusion is not reasonable, then the hypothesis is wrong, the exploration conclusion is negative.Example 1 Known first order function y = kx + b (k ≠ 0) and the inverse-proportion function y = k / 2x at point A (1,1).