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Ethernet 是一种传递速度为10 M bit/s 1-坚持型 CSMA/CD 协议网。确切地讲,它具有以下三点重要特性:1.两次发送(有效的数据包或冲突阻塞信息)的最小间隔(interfram spacing)为9.6μs;2.阻塞信号(jamsignal)长度应为32～48bit(3.2～4.8μs);3.当网络分布接近零时,仍存在冲突的可能性。借助离散的 Markov 链理论,导出了流通量 S 与负载 G 之间的函数关系式。由此得知,在最佳状态(通量=负载)时,流通量却明显下降,这特别对于数据包长度低于500bit 情况,尤为突出。最后,给出模拟结果及通道稳定性分析。
Ethernet is a transmission speed of 10 Mbit / s 1- adhere to CSMA / CD protocol network. Specifically, it has the following three important features: 1. The interfram spacing of two transmissions (valid packets or collision blocking information) is 9.6 μs; 2. The jamsignal length should be 32 ~ 48bit (3.2 ~ 4.8μs); 3. When the network distribution is close to zero, there is still the possibility of conflict. With the help of the discrete Markov chain theory, the functional relation between flux S and load G is derived. This shows that, in the best state (flux = load), the flow was significantly decreased, especially for the packet length less than 500bit situation is particularly prominent. Finally, the simulation results and channel stability analysis are given.