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一、“完弹”模型的建立质量为m1的小球,以初速度V_0沿光滑水平面冲向一个连有轻弹簧的质量为m_2的小球.此后系统具有的最大弹性势能多大?如图1所示.图1解析这是一个完全弹性的“慢”碰撞过程.当系统弹性势能极大时,弹簧压缩量最大,二者相对速度为零,这时m_1、m_2具有相同的速度.设二者共同速度为V,由动量守恒定律得m_1V_0=(m_1+m_2)V①此时系统动能最小,弹性势能最大设为EP.再由机械能守恒定律有
The quality of the first and last-shot models is m1. The ball is rushed along the smooth level at the initial velocity V_0 to a ball with mass m2 attached to a light spring. How large is the maximum elastic potential energy of the system? This is shown in Fig. 1. Fig. 1 Analysis This is a completely elastic “slow” collision process. When the system elastic potential is extremely high, the spring compression is maximum, and the relative velocity of the two is zero. At this time, m_1 and m_2 have the same Speed. Let both the common speed be V, from the law of conservation of momentum m_1V_0 = (m_1+m_2)V1 At this moment, the system kinetic energy is minimum, and the elastic potential energy is set to be the maximum. Then the conservation law of mechanical energy has