【摘 要】
：
设G是一个图,G的独立集Y称为本质集,如果存在{y1,y2}Y,使得dist(y1,y2)=2.本文利用插点方法,给出了关于k或(k+1)连通(k≥2)无爪图G是哈密尔顿的或1哈密尔顿的统一的证明.2
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设G是一个图,G的独立集Y称为本质集,如果存在{y1,y2}Y,使得dist(y1,y2)=2.本文利用插点方法,给出了关于k或(k+1)连通(k≥2)无爪图G是哈密尔顿的或1哈密尔顿的统一的证明.2个结果的充分条件是关于∑ki=0N(Yi)与n(Y)的不等式,这里Y是图G的任一本质集,对于i∈{0,1,…,k},Yi={y1,yi-1,…,yi-(b-1)}Y(yj的下标将取模k+1);b是一个整数,且0＜b＜k+1;n(Y)={v∈V(G):dist (v,Y)≤2}.
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