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在 pH6 2的HAc NaAc缓冲溶液中和溴化十六烷基三甲基铵存在下 ,二氯化双 (甲氧羰乙基 )锡 (简写为R2 SnCl2 )与苯基荧光铜 (PF)形成 1∶2的有色络合物 ,络合物最大吸收波长为 5 60nm ,表观摩尔吸光系数 3 19× 10 4 。R2 SnCl2 中Sn的浓度在 0～ 2 6mg/L范围内符合比尔定律。拟定的方法用于PVC中间产品中R2 SnCl2 的测定 ,结果满意。相对标准偏差为0 76%～ 1 13 % ,回收率为 98 5 %～ 10 1 0 %之间 ,对R2 SnCl2 与PF显色反应的机理进行了探讨。
Bis (carbomethoxyethyl) tin dichloride (abbreviated R2 SnCl2) and phenyl fluorescent copper (PF) are formed in a HAc NaAc buffer solution at pH 6 2 and cetyltrimethylammonium bromide 1: 2 colored complex, the maximum absorption wavelength of the complex is 5 60nm, the apparent molar absorptivity is 3 19 × 10 4. The concentration of Sn in R2 SnCl2 complies with Bill’s law in the range of 0 ~ 26mg / L. The proposed method for the determination of R2 SnCl2 PVC intermediate products, the results are satisfactory. The relative standard deviations (RSDs) ranged from 76% to 113% and the recoveries ranged from 98 5% to 101 0%. The mechanism of the color reaction of R2 SnCl2 with PF was discussed.