【问题】在865后面补上三个数字,组成一个六位数,使它分别能被3、4、5整除。符合这些条件的六位数中,最小的一个是多少?【一般解法】要使这个六位数能被5整除,个位上只能是0或者5,又要使这个六位数能被4整除,末尾只能是0,因此末两位可能是00、20、40、60、80。如果末两位是00,已知的五个数位上的数和为8+6+5+0+0=19,而要使这个数还能被3整除,百位上可填2、5、8,末三位数可为200、500、 [Question] Behind the 865 make up three numbers to form a six-digit number, so that it can be divisible by 3,4,5. What is the smallest of the six digits that match these criteria? [General Solution] To make this six digits divisible by 5, the digits can only be 0 or 5, and the 6 digits can be replaced by 4 Divide, the end can only be 0, so the last two may be 00,20,40,60,80. If the last two digits are 00, the number of known five digits is 8 + 6 + 5 + 0 + 0 = 19, and to make this number divisible by 3, 8, the last three digits can be 200,500,