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两艘潜水艇相距l,以相同的速度v沿一直线航行.后艇的水声定位器发出一声音信号到达前艇并被反射回来.声音在海水中传播的速度为v0,求后艇从发出声音信号至收到回声信号的时间.(2000年初中物理竞赛) 解设后艇发出声音信号到达前艇的时间为t1,声音由前艇反射回后艇经历的时间为t2.由题意得v0t1=l+vt1 ①, l=v0t2+vt2 ②由①式解得t1=l/v0-v ③由②式解得t2=l/v0+v ①
The two submarines are separated by a distance l and follow a straight line at the same speed v. The rear submarine's hydroacoustic positioner sends out a sound signal to the front boat and is reflected back. The speed of sound travels in the seawater is v0. The time when the sound signal is sent to the echo signal. (Physical Physics Competition in the early 2000s) Settling time for the rear boat to send a sound signal to the front boat is t1. The time for the sound reflected from the front boat back to the rear boat is t2. Then v0t1=l+vt1 1, l=v0t2+vt2 2 is solved by formula 1 t1=l/v0-v 3 is solved by formula 2 t2=l/v0+v 1