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题目:一根均匀直棒长为 L,重为 G,以其中点为支点,则直棒处于平衡状态,如图1所示.现将其左端锯掉1/4L,然后在锯断处挂一砝码,直棒仍处于平衡状态,如图2所示,则砝码重力 G’应为: 当此题出现在一次平时测验中时,全年级只有两位同学做对,而其它同学大都选 B 答案.问及选 B 同学的思路,回答如出一辙,挂上的砝码对杠杆的作用效果应与被截去的1/4段
Title: A uniform straight rod of length L, weight G, with its midpoint as the fulcrum, the straight rod is in equilibrium, as shown in Figure 1. Now saw its left end 1/4L, and then hang in the saw One weight, the straight stick is still in balance, as shown in Figure 2, then the weight G’ should be: When this question appears in a normal time test, only two classmates do right at the grade level, while most other students are Select B answers. Ask the ideas of the selected B students. The answer is exactly the same. The effect of the hanging weight on the lever should be equal to the 1/4 segment that is clipped.