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条件分式的求值是初中代数中的一个重点,也是一个难点.除了运用基本方法以外,还应根据条件式和待求式之间的关系,灵活应用所学知识,采用一些特殊方法去求解.一倒数关系例1已知m2+1/m2=4,求m+1/m和m-1/m的值.分析:充分利用m与1/m的互为倒数的关系,可以得到以下的式子:(m±1/m)2=m2±2+1/m2.灵活运用这一变形,便可巧妙地解决此类问题.
Conditional fractional evaluation of the junior high school algebra is also a key, but also a difficult addition to the use of basic methods, but also should be based on the relationship between conditional and to-be-asked, flexible application of knowledge, using some special methods to solve . A reciprocal relationship Example 1 Known m2 + 1 / m2 = 4, find the value of m + 1 / m and m-1 / m Analysis: Take full advantage of m and 1 / m reciprocal relationship between each other, you can get the following (M ± 1 / m) 2 = m2 ± 2 + 1 / m2 The flexibility to use this deformation can be a clever solution to such problems.