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研究了如下形式的作为一阶线性脉冲时滞微分方程的离散情形的脉冲时滞差分方程:xn+1-xn+pnxn-1=0(n>0,n≠m),lx,+1-xn1=btxnt(t=1,2,…).其中pn,k,n,,bt分别满足下列条件:Received date: 2001-07-06Foundation item: This research is supported by the China Natural Science Foundation(10071018)Biography: WANG Jun (1970