关于急刹车和急转弯的讨论在一些刊物上时有出现,多是从理想化模型的角度讨论。本文结合实际,对这一问题进行探讨。如图1所示,设汽车从距离障碍物s的A点发现前面的障碍物,障碍物的宽度为BC=2l,汽车的速度为v,与地面的动摩擦因数为μ,则汽车紧急刹车时的最大滑行距离为s=v~2/(2μg)。汽车紧急转弯 Discussions about sudden braking and sharp turns have appeared in some publications, mostly from the perspective of idealized models. This article combines actuality and discusses this issue. As shown in Fig. 1, let the car find the obstacle in front of the point A from the obstacle s. The width of the obstacle is BC=2l, the speed of the car is v, and the dynamic friction factor with the ground is μ, then when the car is in emergency braking The maximum gliding distance is s=v~2/(2μg). Car emergency turn