本文给大家介绍一种利用最值定义由给定含参函数的最值求解相应参数的方法.先看两道习题的常规解法.例1已知函数f(x)=λ·2x+4x,x∈[0,2]的最小值为-4,求λ的值.解令t=2x,则1≤t≤4,且f(x)=g(t)=λt+t2=(t+λ2)2-λ24.⑴当1≤-λ2≤4,即-8≤λ≤-2时,[f(x)]min=[g(t)]min=-λ24=-4,解得λ=4(舍 In this paper, we introduce a method that uses the most value definition to solve the corresponding parameters from the given value of the given parameter. First look at the conventional solution of two exercises. Example 1 Known function f (x) = λ · 2x + 4x, The minimum value of x∈ [0,2] is -4, and the value of λ is obtained. Letting t = 2x, 1≤t≤4 and f (x) = g (t) = λt + t2 = λ2) 2-λ24. 1 [f (x)] min = [g (t)] min = -λ24 = -4 when 1≤-λ2≤4, that is, = 4 (homes