论文部分内容阅读
1.求函数y=8/|x|-1+(5x-4)~(1/2)0的自变量x的取值范围.2.直线nx+(n+1)y=2~(1/2)(n为正整数)与两坐标轴围成的三角形面积为Sn(n=1,2,…,2000),求S1+S2…+S2000的值.3.已知一次函数的图象经过点(2,2),它与两坐标轴所围成的三角形的面积为1.求这个一次函数的解析式.4.求证:不论k为何值,一次函数(2k-1)x-(k+3)y-k+11=0的图象恒过一定点.5.如图1,在Rt△ABC中,CD是斜边AB上的中线,BC=4,AC=3,点P为CD上
1. Find the range of the value of the argument x of the function y=8/|x|-1+(5x-4)~(1/2)0. 2. The straight line nx+(n+1)y=2~(1) /2) (n is a positive integer) and the area of the triangle enclosed by the two axes is Sn (n=1, 2,..., 2000), and the value of S1+S2...+S2000 is calculated. 3. The graph of the known first-order function. Like the passing point (2,2), the area of the triangle enclosed by it and the two axes is 1. Find the analytical formula of this function.4. Proof: regardless of the value of k, the first function (2k-1)x- The image of (k+3)y-k+11=0 is constant over a certain point. 5. In Fig. 1, in Rt△ABC, CD is the midline on the hypotenuse AB, BC=4, AC=3, point P is on the CD