函数贯穿高中数学的始终,是高考考代的重点,函数的单调性、奇偶性更是考查的热点.在求解函数问题时,如能挖掘潜在条件,巧妙运用函数的性质,常能化难为易,取得意想不到之效.例1已知f(x)=(ma~x-1)/(a~x+1)(a>0,a≠1,m∈R)为奇函数.(1)求m的值;(2)若a>1,解关于x的不等式f(2-x~2) Function throughout the high school mathematics has always been the focus of college entrance examination, the monotony of the function, parity is a hot spot to test in the solution function problems, such as mining potential conditions, the clever use of the nature of the function, (1) It is known that f (x) = (ma ~ x-1) / (a ​​~ x + 1) (a> 0, a ≠ 1, m∈R) ) Find the value of m; (2) If a> 1, solve the inequality f (2-x ~ 2) for x,