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98年厦门市物理统考题:把“6V 3W”与“6V1W”的两个灯泡串联后接入某一个电路中,如果让其中一个灯泡正常发光,电路两端要加多大的电压?(设灯丝电阻不随温度改变)分析:“6V 3W”与“6V 1W”的灯泡串联,接入电路中.由于两灯电阻值不等,串联时同时正常发光是不可能的.到底是哪个灯能正常发光这是解题的关键.可以用假设法来解答,假设其中一个灯能正常发光,计算出应加的电
98 Xiamen Physical Examination Questions: Connect two light bulbs of “6V 3W” and “6V1W” to a certain circuit in series. If one of the bulbs is allowed to glow normally, how much voltage should be applied to both ends of the circuit. ?(The filament resistance does not change with temperature) analysis: “6V 3W” and “6V 1W” bulbs in series, access to the circuit. Because the two lamp resistance values are not equal, it is not possible to emit light at the same time in series. It is the key to solving the problem. Which lamp can emit light normally? It can be answered by the hypothesis method. Assume that one of the lamps can emit light normally and calculate the amount of electricity that should be added.