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在学习中我碰到如下一道几何计数问题,解后颇有感悟,现将粗俗之见陈述如下,仅供读者参考.题目把一个圆周24等分,过其中任意3个分点,可以连成圆的内接三角形,其中直角三角形的个数是()(A)122个.(B)132个.(C)244个.(D)264个.解析我们知道,圆内接直角三角形的直角所对的边必为圆的
In the course of study, I encountered the following problem of geometric counting. After the solution, I was quite aware of it. Now I present the vulgar statements as follows. For readers’ reference only, the title divides a circle into 24 equal parts and passes any three of them. The circle is inscribed in a triangle, in which the number of right triangles is () (A) 122. (B) 132. (C) 244. (D) 264. Analysis We know that the circle is right angled right angle triangle The right side must be round