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题:某黑匣子中有三个电阻,如何接法不知,外部只有三个接线柱 A、B、C,如图(1)所示.若在 A、C 间加10伏电压,在 B、C 间接一电压表,电压表的示数为7.5伏,如果在 B、C间接一电流表,电流表示数为0.55安.若在 B、C 间加10伏电压时,用电压表测得 A、C 两端间的电压为6伏,用电流表接在 A、C 两端间,电流表示数为0.55安.试求三只电阻的阻值,并画出三只电阻的连接方法.简析:依题意,三只电阻不可能采用串联或并联.可设为“T”形和“Δ”形两种接法如图2,
Problem: There are three resistors in a black box. I don’t know how to connect them. There are only three external terminals A, B, and C on the outside, as shown in (1). If you add 10 volts between A and C, they are indirectly connected to B and C. A voltmeter, the voltmeter shows the number of 7.5 volts, if in B, C indirectly an ammeter, the current represents the number of 0.55 A. If in B, C plus 10 volts, with a voltmeter measured A, C two The voltage between the terminals is 6 volts, connected between the two ends of A and C with an ammeter. The current is 0.55 A. Try the resistance of the three resistors and draw the connection method of the three resistors. Meaning, the three resistors cannot be connected in series or in parallel. It can be set as the “T” shape and the “Δ” shape as shown in Figure 2.