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我国古代数学名著《孙子算经》下卷有这样一道题目:今有雉兔同笼,上有三十五头,下有九十四足,问雉兔各几何。这道题编得十分有趣,在《孙子算经》原书里,解这道题用了一种别致的简便解法:取脚数94的一半,得47,用脚数的一半减去头数35,得12,这就是兔的只数;再拿头数35减去兔的只数12,得23,这就是鸡的只数。“鸡兔同笼”问题还有多种解法,比如仍以《孙子算
The ancient Chinese mathematical masterpiece “The Sun Tzuosoji” scroll there is such a topic: There are pheasant rabbits with the cage, there are thirty-five, there are ninety-four feet, asked the pheasant rabbit geometry. This is a very interesting compilation. In the original Book of the Sun Tzu, the solution to this problem uses a simple and easy solution: take half of the number of feet 94 to 47, and subtract the number of heads from half of the number of feet 35, got 12, this is the only rabbit; then take the first few 35 minus the rabbit’s number 12, 23, which is the only chicken. “Chicken rabbit with cage ” There are many solutions to the problem, such as still "grandchildren count