论文部分内容阅读
在中学有机化学习题里,经常会遇到这样一类的问题:已知某烃中碳原子个数和分子量,确定该烃是哪种类型的烃。现在普遍的做法是用各类烃的通式来一一的套,这种方法的缺点是费时间。我在教学中摸索了一种简单快速的方法供大家参考: 在中学有机化学里,烃类有以下几种: 烷烃通式C_nH_(2n+2) 烯烃(环烷烃)通式C_nH_(2n) 炔烃(二烯烃)通式C_nH_(2n-2) 芳香烃通式C_nH_(2n-(?)) 将上述各类烃的通式合并,用一个式子来表示:C_nH_(2n-x)(-2≤x≤6) 假如某烃的分子量为M,则有
In the middle school organicization problem, one often encounters the problem of knowing the number and molecular weight of carbon atoms in a certain hydrocarbon and determining which hydrocarbon the hydrocarbon is. It is now common practice to use a generic formula for all types of hydrocarbons. The disadvantage of this method is that it takes time. I have explored a simple and fast method in teaching for your reference: In the middle school organic chemistry, hydrocarbons are the following: Alkanes General formula C_nH_(2n+2) Alkenes (naphthenes) General formula C_nH_(2n) Alkynes Hydrocarbons (diolefins) General formula C_nH_(2n-2) Aromatic general formula C_nH_(2n-(?)) Combining the general formulas of the above classes of hydrocarbons, expressed by one formula: C_nH_(2n-x)(- 2≤x≤6) If the molecular weight of a hydrocarbon is M, then there is