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苯并-15-冠-5四溴合铟(III)酸钾,KInBr_4(C_(14)H_(20)O_5)_2,晶体属单斜晶系,空间群为C_(2h)~5-P2_1/n,晶胞参数α=14.402(3),b=15.082(3),c=17.262(5)A,β=93.42(2)°,Z=4.非氢原子的位置由Patterson函数及Fourier合成法找出,经全矩阵最小二乘法修正R=0.057.结构分析表明K~+和两个苯并-15-冠-5(B-15-C-5)分子直接配位,对阴离子为InBr_4~-,具有四面体构型.InBr_4~-与配阳离子K(B-15-C-5)_2~+依靠静电引力结合为离子对.由此说明,In(III)在过量KBr存在下可以被B-15-C-5定量地萃取至有机相中.
The crystal of the complex is monoclinic with space velocity of C 2h ~ 5-P 2_1, K 2 O 5 -Pb-4 (C_ (14) H_ (20) O_5) / n, cell parameters α = 14.402 (3), b = 15.082 (3), c = 17.262 (5) A, β = 93.42 (2) °, Z = 4. The positions of non-hydrogen atoms are determined by the Patterson function and Fourier (R = 0.057). The structural analysis showed that K ~ + was directly coordinated with two molecules of B-15-C-5 and the anions were InBr_4 ~ -, with a tetrahedral configuration.InBr_4 ~ - with the cation K (B-15-C-5) _2 ~ + rely on electrostatic attraction for the ion pair.Thus, In (III) in the presence of excess KBr Can be quantitatively extracted into the organic phase by B-15-C-5.