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四、筒壳的位移计算方程(47)的解为:(第一座标系)W_1=e~(β_1x_1)(A_1cosβ_1x_1+A_2sinβ_1x_1)+e~(-β_1x_1)(A_3cosβ_1x_1+A_4sinβ_1x_1)+((?)/k) (62)其中:k=4Dβ_1~4 (63)引进双曲函数:(?)(64)则:W_1=C_1chβ_1x_1cosβ_1x_1
Fourth, the solution of the cylinder displacement calculation equation (47) is: (first coordinate system) W_1=e~(β_1x_1)(A_1cosβ_1x_1+A_2sinβ_1x_1)+e~(-β_1x_1)(A_3cosβ_1x_1+A_4sinβ_1x_1)+((? )/k) (62) where: k=4Dβ_1~4 (63) Introducing the hyperbolic function: (?)(64) then: W_1=C_1chβ_1x_1cosβ_1x_1