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在新旧教材中都有这样一道题目 :问题 1 求经过两圆 x2 + y2 + 6 x - 4=0和 x2 - y2 + 6 y - 2 8=0的交点 ,并且圆心在直线 x - y - 4=0上的圆的方程 (老教材《平面解析几何》全一册 (必修 ) P70 ;新教材《数学》第二册 (上 ) (试验修订本 .必修 ) P82 ) .此题一般有两种解法
In both old and new textbooks there is such a problem: Problem 1 Find the intersection of two circles x2 + y2 + 6 x - 4 = 0 and x2 - y2 + 6 y - 2 8 = 0, and the center of the circle is on the straight line x - y - 4 Equation of the circle on =0 (Old textbook “Plane Analytical Geometry” (1) (required) P70; New textbook “Mathematics” 2 (on) (Test Revision. Compulsory) P82). There are two general types of questions. solution