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在概率的学习中,老师给我们布置了如下一题:8个排球队中有两个强队,任意将这8个队分成两组(每组4个队)进行比赛,求这两个强队被分在同一个组内的概率．此题经过我们研究,找到了如下几种解法．解法一设“两个强队同组”为事件C(以下各解法中,C的含义相同)．若视组与组之间无顺序,则8个队平均分成两组的分法应是1/2C84=35(种),而两个强队分在同一组的分法是C62C44=15种,故P(C)=15/35=3/7．
In the study of probability, the teacher laid out the following question for us: There are two strong teams in the eight volleyball teams. Arbitrarily divide the eight teams into two groups (four teams each) to compete. The probability that the team is divided into the same group. After this topic we studied, we found the following solutions. Solution One sets “two strong teams in the same group” as event C (in the following solutions, C has the same meaning). If there is no order between the visual group and the group, the average score of the eight teams divided into two groups should be 1/2C84=35 (species), and the division method of the two strong teams in the same group is C62C44=15. Therefore P(C)=15/35=3/7.