一、得出结论引例已知A,B是直线l上任意两点,O是外一点,求证:对直线l上任意一点P,存在实数t,使OP关于基底{OA,OB}的分解式为OP=(1-t)·OA+tOB.并且,满足等式的点P一定在直线l上.证明设点P在直线l上,则由平行向量基本定理可知,存在实数t,使AP=tAB=t(OB-OA).所 First, it is concluded that A and B are any two points on a straight line l and O is a little extra point. Prove that for any point P on the straight line l, there exists a real number t such that the resolution of OP on the basis of {OA, OB} For the OP = (1-t) · OA + tOB. And, to meet the equation of the point P must be on the straight line I. Prove that the set point P in a straight line l, then the basic theorem of parallel vectors shows that there is a real number t, AP = tAB = t (OB-OA)