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以BaCO3、Co3O4、Fe2O3和Nb2O5粉末为原料,通过固相反应合成了钙钛矿型复合氧化物Ba1.0Co0.7Fe0.2Nb0.1O3-δ.利用XRD、SEM和TGA-DSC同步热分析仪等研究了合成该材料的反应过程.结果发现,在固相反应法合成Ba1.0Co0.7Fe0.2-Nb0.1O3-δ的过程中,首先出现的是BaCoO3、BaFeO2.9相和Ba5Nb4O15相,在1 473 K烧结10 h能够得到立方钙钛矿相的Ba1.0-Co0.7Fe0.2Nb0.1O3-δ.通过分析,整个反应过程分为两个阶段:第一阶段为BaCO3和Co3O4、Fe2O3、Nb2O5之间的加成反应;第二阶段为加成反应生成的BaCoO3、BaFeO2.9和Ba5Nb4O15三相之间逐渐固溶生成均相Ba1.0Co0.7Fe0.2Nb0.1O3-δ,此过程伴随有氧的脱出.
Ba1.0Co0.7Fe0.2Nb0.1O3- δ was synthesized by solid-state reaction using BaCO3, Co3O4, Fe2O3 and Nb2O5 powders as raw materials, XRD, SEM and TGA-DSC simultaneous thermal analyzer The reaction process of the synthesis of the material was studied. It was found that during the synthesis of Ba1.0Co0.7Fe0.2-Nb0.1O3-δ by solid-state reaction, the first phase of BaCoO3, BaFeO2.9 and Ba5Nb4O15 phase, Ba1.0-Co0.7Fe0.2Nb0.1O3-δ can be obtained by sintering at 1 473 K for 10 h. The whole reaction process is divided into two stages: the first stage is BaCO3 and Co3O4, Fe2O3, Nb2O5; the second stage is the homogeneous solution of Ba1.0Co0.7Fe0.2Nb0.1O3-δ between three phases of BaCoO3, BaFeO2.9 and Ba5Nb4O15 formed by the addition reaction, accompanied by Oxygen prolapse.