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在MgO坩埚中于1600℃下进行了CaO=25～50％的CaO—MgO_(sat)—SiO_2—FeO_n(及少量MnO、Al_2O_3和CaF_2)渣系与铁液之间的L_p,平衡实验。通过多种回归方程的比较,得出该实验条件下磷平衡分配比的最佳表达式为 lg(％P)/[％P]=0.0491[(％CaO)+0.7(％MgO)]+2.5lg(％TFe)+0.5lg(％P_2O_5)-3.505 N=34,R=0.939,S=0.117其S值较Healy公式的(S±0.4)小。并且。(1)当[(％CaO)+0.7(％MgO)]/(％TFe)=2时,(％P)/[％P]值最大,(2)(％P)/[％P]随(％Fe_2O_3)/[(％Fe_2O_3)+[(％FeO)]的增大和(％SiO_2)的减少而增大的关系十分显著。从而提出生产中应控制(％TFe)=1/2[(％CaO)+0.7(％MgO)],提高(Fe_2O_3)含量和降低(SiO_2)含量。
The L_p equilibrium experiment between CaO-MgO_ (sat) -SiO_2-FeO_n (with a small amount of MnO, Al_2O_3 and CaF_2) slag and molten iron at CaO = 25 ~ 50% was carried out in a MgO crucible at 1600 ℃. Through the comparison of multiple regression equations, the optimal expression of phosphorus balance distribution ratio under this experimental condition is obtained as: lg (% P) / [% P] = 0.0491 [(% CaO) +0.7 (% MgO)] + 2.5 (% TFe) + 0.5lg (% P_2O_5) -3.505 N = 34, R = 0.939, S = 0.117 The S value is smaller than (S ± 0.4) of Healy’s formula. and. (1) The value of (% P) / [% P] is the largest when [(% CaO) +0.7 (% MgO)] / (% TFe) (% Fe_2O_3) / [(% Fe_2O_3) + [(% FeO)] increases with the decrease of (% SiO_2). Therefore, it is proposed that% TFe = 1/2 [(% CaO) +0.7 (% MgO)], increase (Fe_2O_3) and decrease (SiO_2) in production.