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一、从一道“祖冲之杯”竞赛题说起 第七届“祖冲之杯”数学邀请赛的第五题是: 设实数a、b、c满足(a+b)(a+b+c)<0. 求证:(b—c)~2>4a(a+b+c). 《数学教师》于1995.2期上刊登此题时给出的参考答案为:设辅助二次函数
First, from a “Zu Chong Cup” contest title talking about the seventh “Zu Chong Cup” mathematical tournament fifth question is: Set the real number a, b, c to meet (a + b) (a + b + c) <0. Proof: (b—c)~2>4a(a+b+c). The reference answer given by “Mathematics Teacher” in 1995.2 was: Assist secondary function