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数学通报1958年4月号“初中算术中的一个錯誤”一文談到初中算术p.242近似商取法里余数的說法是錯誤的。这一意見很多人贊同。但个人觉得有值得商榷的地方。今提出一个改进叙述的办法,希望能起到一点集思广益的作用,并求大家指正。如果认为教材上說法在語句上还不够明显,我們为了方便而又使文字簡洁,我认为可把近似商取法这样来叙述:“在除到指定的小数位时,为了使所取的近似商的誤差小于这个指定小数位上的单该的1/2,如果这时的余数其相当于这个小数位上单位的倍数小于除数的1/2,就取不足近似商;……”。这
The statement in the April 1958 mathematics bulletin “An error in junior high school arithmetic” mentioned in the junior high school arithmetic p.242 approximate quotient remainder is wrong. Many people agree with this opinion. But personally feel there is something that is worth discussing. This time, we propose a method of improving narrative, hoping to play a role in brainstorming, and ask everyone to correct me. If we think that the statement on the teaching material is not obvious enough in terms of sentences, we have made the text concise for convenience. I think the approximate quotient can be described as follows: “When dividing to the specified decimal place, in order to make the approximate quotient The error is less than one-half of the specified decimal place. If the remainder at this time is equivalent to the multiple of the unit in this decimal place is less than 1/2 of the divisor, the less-approximate quotient is taken....". This