函数-不等式恒成立问题是中学数学的重要内容,也是近年高考的一个热点问题.研究高考试题,不难发现函数-不等式问题立意深刻,是有效地甄别考生能力的一类好试题.本文中例谈高考中函数-不等式恒成立问题的求解策略,以飨读者.一、直接法例1(2007年重庆卷)已知函数f(x)=ax~4lnx+bx~4-c(x>0)在x=1处取得极值-3-c,其中a,b,c为常数.(Ⅰ)试确定a、b的值;(Ⅱ)讨 Function-inequality constant problem is the establishment of an important part of high school mathematics, but also a hot spot in recent years college entrance examination exam questions, it is not difficult to find that the function-inequality conception is profound, is a good screening of candidate’s ability a good test questions. On the college entrance examination function-inequality constant solution to the problem of solving strategies, readers.A direct law 1 (2007 Chongqing volume) known function f (x) = ax ~ 4lnx + bx ~ 4-c (x> 0) Obtain the extreme value of -3-c at x = 1, where a, b and c are constants. (Ⅰ) Determine the values ​​of a and b; (ii)