《数学通报》2005年第44卷第1期“n等角平分线的一个定理”一文,通过引理,证明定理.实际上,可以简单一些.事实上,△ABC顶角A的n等角平分线交对边BC于B1,B2,…,Bn-1,形成n个等高的三角形:△ABB1,△AB1B2,…,△ABn-1C.n条边BB1,B1B2,…,Bn-1C的比,等于这n个三角形面积的比.而这n “Mathematics Bulletin”, Vol. 44, No. 1, 2005, “A Theorem for the n-diagonal Bifurcation”, which proves the theorem through lemma. In fact, it can be simpler. In fact, the A-corner angle of ABC is equal to n. The bisectors BC intersect at B1, B2,..., Bn-1 to form n triangles of equal height: ΔABB1, ΔAB1B2,..., ΔABn-1C.n edges BB1, B1B2,..., Bn-1C. The ratio is equal to the ratio of the n triangular areas. And this