第33届美国数学奥林匹克第5题为:设a,b,c均为正实数,证明:(a5-a2+3)(b5-b2+3)(c5-c2+3)≥(a+b+c)3.文[1]推广了上述不等式,得到如下结果:设ai0,i=1,2,…,3k,k为自然数,则∏3ki=1(ai5k-ai2k+3k)≥(∑3ki=1ai)3k.文[2]将[1]的结论再推广为:设ai0,i=1,2,…,n,α,β为正实数,则∏ The 33rd American Mathematical Olympiad Question 5: Let a, b, and c be positive real numbers, and prove that: (a5-a2+3)(b5-b2+3)(c5-c2+3)≥(a+b) +c) 3. The paper [1] generalizes the above inequality and obtains the following result: Let ai0,i=1,2,...,3k,k be a natural number, then ∏3ki=1(ai5k-ai2k+3k)≥(∑ 3k = 1ai) 3k. The article [2] generalizes the conclusion of [1] as follows: Let ai0,i=1,2,...,n,α,β be positive real numbers, then