我在中考阅卷中,发现了学生的一些独特解法,同时,也看到许多典型错误,这些解题方法和典型错误可能对大家有一定启发和借鉴意义1现摘撷如下,以飨读者1例1(2013.重庆)如图1,在矩形ABCD中,E、F分别是边AB、CD上的点,AE=CF,连接EF,BF,EF与对角线AC交于O点,且BE=BF,∠BEF=2∠BAC.(1)求证:OE=OF; I was in the exam papers, found some unique solutions to students, but also saw many typical mistakes, these problem-solving methods and typical mistakes may have some inspiration and reference for everyone 1 Now pick as follows to readers 1 case 1 In the rectangular ABCD, E and F are the points on the sides AB and CD, respectively, AE = CF, connecting EF, BF, EF and the diagonal AC at O, and BE = BF, ∠BEF = 2∠BAC. (1) Proof: OE = OF;