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应用团簇+胶粘原子模型在三元Fe-B-Y合金系中设计三元合金成分,选择最密堆的CN10Archimedes八面体反棱柱Fe8B3作为基本团簇,Y为胶粘原子。在此基础上添加3at%Nb作为微合金化元素形成四元合金。以适量的Ni替换Fe,形成五元合金[(Fe100-xNix)8B3-Y]97-Nb3。结果表明,当Ni的含量小于30at%时,均可形成直径为2mm的块体非晶合金,其中,合金[(Fe94Ni6)8B3-Y]97-Nb3具有最大的Tg、Tx和Trg值,分别为:884K、972K和0.634。
In the ternary Fe-B-Y alloy system, the ternary alloy composition was designed using the cluster + glue atom model. The most densely packed CN10Archimedes octahedral anti-prism Fe8B3 was chosen as the basic cluster, and Y was the gluey atom. On this basis, adding 3at% Nb as a microalloying element to form a quaternary alloy. Fe is replaced with an appropriate amount of Ni to form a ternary alloy [(Fe100-xNix) 8B3-Y] 97-Nb3. The results show that when the content of Ni is less than 30at%, the bulk amorphous alloy with the diameter of 2mm can be formed, in which the alloy [(Fe94Ni6) 8B3-Y] 97-Nb3 has the maximum Tg, Tx and Trg For: 884K, 972K and 0.634.