有一个常见的命题:如果不等式f(x)≥0的解集是A,那么不等式f(x)0的解集是A的补集.文[1]称此命题不真,是一个习以为常的错误,并举反例:不等式xx--mm≥0的解集是(-∞,m)∪(m,+∞),然而不等式x-mx-m0的解集不是上述解集的补集{m},而是.从逻辑上看,该命题显然成立,但文[1]又确实 There is a common proposition: if the solution set of inequality f(x) ≥ 0 is A, then the solution set of inequality f(x)0 is the complement of A. [1] This proposition is not true and is a familiar one. Error, and counterexample: The solution set of inequality xx--mm≥0 is (-∞,m)∪(m,+∞), but the solution set of inequality x-mx-m0 is not a complement of the above solution set {m} But logically, this proposition is obviously established, but the text [1] is indeed