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对于二次函数y=ax~2+bx+c(a≠0),可通过配方法将其化为顶点式y=a(x+b/2a)~2+4ac-b~2/4a(a≠0),可知:
For the quadratic function y=ax~2+bx+c(a≠0), it can be transformed into the vertex expression y=a(x+b/2a)~2+4ac-b~2/4a ( a≠0), we can see: