1深挖“人船模型”图1如图1,船浮于平静的水面上,人站在船的右端,人、船质量分别为m、M,船长为l,不计水的阻力.二者水平方向不受外力,故动量守恒.若人以速度v1向左行走,则船以速度v2向右后退,故有mv1-Mv2=0.于是有vv21=mM.(1)若人船位移分别为s1、s2,人船动能分别为Ek1、Ek2,则 1Deeply excavating the “human ship model” Figure 1 As the ship floats on a calm surface, people stand on the right side of the ship. The mass of the person and the ship are m and M respectively, the length of the ship is l, and the water resistance is not counted. The horizontal direction is not affected by external forces, so the momentum is conserved. If a person walks to the left at speed v1, the ship retreats to the right at speed v2, so there is mv1-Mv2=0. Then there is vv21=mM. (1) If the person’s ship moves respectively For s1, s2, the kinetic energy of people’s ships are Ek1, Ek2, respectively.