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４－碘苯氧乙酸可以由苯氧乙酸和碘化钠或碘化钾或碘，在氧化剂碘酸钠或碘酸钾或高 锰酸钾的存在下，在碱性介质中进行反应而获得，产率７９—８８％，较之文献上已报导的 最佳产率［２］提高一倍。此法只需加入计算量的碘代剂，又可用水为溶剂，反应时间短， 操作简便，总的看来，较适于生产。如果把氧化剂改为氯酸钾、过氧化氢或漂白粉，或不加氧化剂，则无４－碘苯氧乙酸 生成。 如果在酸性介质中，由苯氧乙酸和碘在碘酸钠存在下进行反应，则产率仅为４０—５５％， 并需用冰醋酸为溶剂。 如果由苯氧乙酸和一氯化碘作用，以冰醋酸为溶剂，也可获得４－碘苯氧乙酸，产率 ７６—８０％。
4-Iodophenoxyacetic acid can be obtained from phenoxyacetic acid and sodium iodide or potassium iodide or iodine by reaction in an alkaline medium in the presence of an oxidizing agent sodium iodate or potassium iodate or potassium permanganate, yield 79-88%, doubling the best yield already reported in the literature [2]. This method simply by adding the calculated amount of iodine agent, but also water as a solvent, the reaction time is short, easy to operate, in general, more suitable for production. If the oxidant is changed to potassium chlorate, hydrogen peroxide or bleach, or without an oxidizer, no 4-iodophenoxyacetate is formed. If the reaction is carried out in acidic medium with phenoxyacetic acid and iodine in the presence of sodium iodate, the yield is only 40-55% and glacial acetic acid is used as the solvent. If the role of phenoxyacetic acid and iodine monochloride, glacial acetic acid as a solvent, but also 4 - iodophenoxy acetic acid, the yield of 76-80%.