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在讲完双曲线性质之后,笔者给出2014年高考数学浙江卷理科第16题进行讲解,在讲解过程中几经波折,终现原貌。现将讲解过程整理如下,与大家交流。题目:设直线x-3y+m=0(m≠0)与双曲线x~2/a~2-y~2/b~2=1(a>0,b>0)两条渐近线分别交于点A,B,若点P(m,0)满足|PA|=|PB|,则该双曲线的离心率是____。出示题目后,笔者按照参考答案进行讲评,过程如解法1。
After the completion of the hyperbolic nature, I gave a 2014 college entrance examination math Zhejiang curling section 16 to explain, in the process of explaining several times after the twists and turns, the original appearance. Now explain the process as follows, to share with you. Subject: Let the two asymptotes of the line x-3y + m = 0 (m ≠ 0) and the hyperbolic x ~ 2 / a ~ 2 ~ y ~ 2 / b ~ 2 = 1 Respectively, to point A, B, if the point P (m, 0) to satisfy | PA | = | PB |, then the hyperbolic eccentricity is ____. Show the title, the author in accordance with the reference answer to comment, the process as solution 1.