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文[1]给出了如下不等式:设a,b>0,若ab≥1/2,则1/(1+a2)+1/(1+b2)≤1+1/(1+(a+b)2)当且仅当a=b=2～(1/2)/2时等号成立.本文给出不等式①的一个类比.
The following inequality is given in [1]: Suppose that a, b> 0, if ab≥1 / 2, 1 / (1 + a2) + 1 / (1 + b2) ≤1 + 1 / (1+ + b) 2) The equality is true if and only if a = b = 2 ~ (1/2) / 2. This article gives an analogy to inequality ①.