(-)-Menthol reacts with phosphorus trichloride to afford menthyl phosphorodichloridite 2,which further reacts with racemic 1, 1'-binaphthalene-2, 2'-diol to give phosphite (±)-3 in the presence of triethylamine. +(±)-3 can be easily separated by fractional crystallization to form the crystal (+)-(S)-3 and the mother liquor (-)-(R)-3. Then both the crystal and the mother liquor are treated with AcOH-H20 to obtain enantiomeric pure (-)-(S)-1 and (+)-(R)-1 respectively, with enantiomeric excess up to 99.7%.